How many numbers satisfy the condition a 3 B 3 c 3 ABC where ABC is a three digit number?

= 5040, which is a four-digit number. But abc is a three-digit number. If any of the digits in abc is 7, 8, or 9, we will get a four-digit number.

What is the general form of 2 digit number?

Thus, any two-digit number can be written in a general form as 10 × x + y i.e 10x + y, where x is the digit in tens place which can be any digit from 1 to 9 and y is the digit in tens place that can be any digit from 1 to 9.

How many 3-digit numbers are there?

Therefore there are 900 three-digit numbers in all.

How do you write a three digit number as a CBA?

Let’s write a three digit number as abc. When we reverse the digits, we get cba. Suppose abc is the larger number, and let’s subtract the smaller number. We can more easily do this by writing the numbers in expanded form:

What is the generalised form of a four-digit number ABDC?

Write the correct answer. 1. Generalised form of a four-digit number abdc is Solution: The correct answer is option (c) 1000 a + 100 b + 10 d + c We know that, the numbers are expressed as the sum of the product of it digits with the respective place value. So the generalised form of abdc is 1000 a + 100 b + 10 d + c 2.

Is ABC+BCA+CAB divisible by 111?

Let abc be a three digit number. Then abc + bca + cab is not divisible by Hence, abc+bca+cab is divisible by 111 and also it is divisible by the factors of 111. Here, 3 and 7 are the factors of 111, and a+b+c is also a factor of 111 (a+b+c).

Is abc-cba divisible by 18?

So, all the numbers which are the factors of 99 will also be divisible by abc-cba Here, 9, 11 and 33 are the factors of 99. But 18 is not a factor of 99. Hence abc- cba is not divisible by 18. 5. The sum of all the numbers formed by the digits x, y and z of the number xyz is divisible by